Detrmine whthere the sequence converges

An = 2((n+1)!) + 4^n / 2(n!)n^2

1) determine whether it converges and if it does, find the limit of the sequence {An}

I realise that i need to find the dominant term of the sequnece and to divide by this and so on, but i have not seen an example where (n+1)! is an element of the sequence and this has thrown me. Any help would be highly appreciated!! Limits is not my forte! :(

Re: Detrmine whthere the sequence converges

Quote:

Originally Posted by

**raggie29** An = 2((n+1)!) + 4^n / 2(n!)n^2

1) determine whether it converges and if it does, find the limit of the sequence {An}

Which is it

Re: Detrmine whthere the sequence converges

The first one. Thanks. :)

Re: Detrmine whthere the sequence converges

Quote:

Originally Posted by

**raggie29** The first one. Thanks.

Why don't you bother to use grouping symbols?

The way you posted the expression, it actually reads as the second one.

What can you say about

Re: Detrmine whthere the sequence converges

It is of form of a basic null sequence and hence = 0?

Re: Detrmine whthere the sequence converges

Quote:

Originally Posted by

**raggie29** It is of form of a basic null sequence and hence = 0?

So what is the overall answer?

Re: Detrmine whthere the sequence converges

Re: Detrmine whthere the sequence converges

Or is it, = 0? since 1/n and 1/n^2 are both basic null sequences?