Hey Launcher.
Re-arranging we get AX - CX = B which implies (A-C)X = B which implies X = (A-C)^(-1)*B.
I need to find out how to solve a system of equations with the given matrix form:
AX=CX+B;
I know I need to make it in the form of X= with inverse of A and C as well as using the identity matrix
What I have guessed at the moment is
X= (I-A)^-1 + (I-C)^-1 + B
I am using excel as I have an equation I have to solve with this but if I can figure out the formula for this I can solve the problem fairly easy.
Thanks!
Oh wow thanks! I knew I had to re arrange them one way or another but on my other examples I have had to use the Identity matrix in with my equation to solve the problem. However, X= (A-C)(-1)*B looks like it may do the trick as well! I will try this out in excel with my given equation now and see what I come up with!
This is the equation I am trying to solve for X which is teh x,y,z,w matrix.