Greetings!

I have a 2 x 2 matrix

3 1

2 0

I will calculate det(A^{3}).

Formula is a_{11}a_{22}-a_{12}a_{21.}

So, 3*0 - 1*2 and that makes det = -2

Thus, det(A^{3}) = (-2)^{3}= -8

And det(A^{-3}) would be (-2)^{-3 }= -0,125

I think I have calculated correctly. ?