Rearranging exponential equation
Hi,
I've tried this on a Maths teacher friend of mine, who is currently stumped, so I hope it classes as 'advanced'. Essentially, I'm trying to rearrange the following equation:
x = y / [A - e^(By)]
to express y in terms of x. Is this possible?
Thanks.
Re: Rearranging exponential equation
Hey mpylon.
What I will do is use implicit differentiation to see if you can separate the variables so that they can be calculated independent of each other.
d/dx(Ax - xe^(By)) = d/dx(y)
dy/dx
= A - d/dx(xe^(By))
= A - [e^(By) + Bx*e^(By)dy/dx] So this implies:
dy/dx[1 + Bxe^(By)] = A - e^(By) or
dy/dx = [A - e^(By)]/[1 + Bxe^(By)]
This looks like all derivatives will involve x's and y's which means that you can't get y as a function purely of x (or the other way around unless you use specific restrictions or find a parameterization.
Re: Rearranging exponential equation
Quote:
Originally Posted by
chiro
Hey mpylon.
What I will do is use implicit differentiation to see if you can separate the variables so that they can be calculated independent of each other.
d/dx(Ax - xe^(By)) = d/dx(y)
dy/dx
= A - d/dx(xe^(By))
= A - [e^(By) + Bx*e^(By)dy/dx] So this implies:
dy/dx[1 + Bxe^(By)] = A - e^(By) or
dy/dx = [A - e^(By)]/[1 + Bxe^(By)]
This looks like all derivatives will involve x's and y's which means that you can't get y as a function purely of x (or the other way around unless you use specific restrictions or find a parameterization.
Why are you differentiating at all? It should be obvious that y can't be isolated because it appears as both an exponent and a polynomial...
Re: Rearranging exponential equation
The point is to show that the functions change depends on its current value which shows its implicit.
Recall that a function is uniquely determined by its Taylor series and one way to show implicit behavior is through its derivative.
Re: Rearranging exponential equation
Re: Rearranging exponential equation
Thanks "a tutor", the Lambert's W function was the way to go, although below a certain number the Lambert's W function gives complex numbers. Is there any way round this?
Re: Rearranging exponential equation
No worries, it was a quirk of the Excel function I downloaded, but have solved it. Thanks for your help.