Hello everyone!Can anyone help me please ? I've got a serious problem in maths with the non-diagonalisable matrices!

A is a matrix

[3 1 0]

[-4 -1 0]

[4 -8 -2]

det |A-λI| = (-2-λ)(λ-1)^2

Thus, we find 2 eigen values:

λ= -2 (order 1)

λ= 1 (order 2)

One eigen vector for λ = -2 is v1 = [0,0,1]

The first eigen vector for λ = 1 is v2= [3, -6, 20]

There is no second independent eigen vector for λ = 1 so the matrix is not diagonalisable!

How can we find A' and P the passage matrix anyway ?

Thanks!! I'm desperate (((((((((