Thread: value of x

solve for x

(19x-34)^2 + 68 = 68x


im trying to solve this in long method but i seems like the method is hard to factor

(19x)^2 - 2(19x)(34)x + 34^2 + 68 = 38x


is this any short method to find the x?

Originally Posted by rcs

solve for x
(19x-34)^2 + 68 = 68x
is this any short method to find the x?

The answer is no.

Originally Posted by rcs

solve for x

(19x-34)^2 + 68 = 68x


im trying to solve this in long method but i seems like the method is hard to factor

(19x)^2 - 2(19x)(34)x + 34^2 + 68 = 38x


is this any short method to find the x?

What you have so far is incorrect but probably just a typo- you should have 2(19)(34)x. There is no "x" with the 19. In any case, I can see no reason not to finish it:
361x^2- 1292x+ 1156= 38x which gives 361x^2- 1330x+ 1156= 0.

If you cannot factor that, use the quadratic formula.

thanks Guys