solve for x

(19x-34)^2 + 68 = 68x

im trying to solve this in long method but i seems like the method is hard to factor

(19x)^2 - 2(19x)(34)x + 34^2 + 68 = 38x

is this any short method to find the x?

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- Dec 22nd 2012, 06:16 AM #1

- Dec 22nd 2012, 06:21 AM #2

- Dec 22nd 2012, 06:29 AM #3

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## Re: value of x

What you have so far is incorrect but probably just a typo- you should have 2(19)(34)x. There is no "x" with the 19. In any case, I can see no reason not to finish it:

361x^2- 1292x+ 1156= 38x which gives 361x^2- 1330x+ 1156= 0.

If you cannot factor that, use the quadratic formula.

- Dec 22nd 2012, 06:39 AM #4