solve for x
(19x-34)^2 + 68 = 68x
im trying to solve this in long method but i seems like the method is hard to factor
(19x)^2 - 2(19x)(34)x + 34^2 + 68 = 38x
is this any short method to find the x?
361x^2- 1292x+ 1156= 38x which gives 361x^2- 1330x+ 1156= 0.
If you cannot factor that, use the quadratic formula.