# value of x

• Dec 22nd 2012, 06:16 AM
rcs
value of x
solve for x

(19x-34)^2 + 68 = 68x

im trying to solve this in long method but i seems like the method is hard to factor

(19x)^2 - 2(19x)(34)x + 34^2 + 68 = 38x

is this any short method to find the x?
• Dec 22nd 2012, 06:21 AM
Plato
Re: value of x
Quote:

Originally Posted by rcs
solve for x
(19x-34)^2 + 68 = 68x
is this any short method to find the x?

• Dec 22nd 2012, 06:29 AM
HallsofIvy
Re: value of x
Quote:

Originally Posted by rcs
solve for x

(19x-34)^2 + 68 = 68x

im trying to solve this in long method but i seems like the method is hard to factor

(19x)^2 - 2(19x)(34)x + 34^2 + 68 = 38x

is this any short method to find the x?

What you have so far is incorrect but probably just a typo- you should have 2(19)(34)x. There is no "x" with the 19. In any case, I can see no reason not to finish it:
361x^2- 1292x+ 1156= 38x which gives 361x^2- 1330x+ 1156= 0.

If you cannot factor that, use the quadratic formula.
• Dec 22nd 2012, 06:39 AM
rcs
Re: value of x
thanks Guys