Re: Finding unknown matrix

As I understand you, you don't know anything about the entries in X Y or Z? Are you given any further information?

If Y is invertible, then you can right-multiply each side by the inverse of Y and then X will be similar to Z.

One solution: if Y is the zero matrix, the equation will always be true. If X = Z, then Y is the identity matrix, or some other matrix with which X commutes. The most general rule I know of is that two matrices will commute iff they are both diagonalizable to the same basis. Some 2x2 matrices, of course, are not diagonalizable at all.

Re: Finding unknown matrix

Firstly thanks for considering my querey =)

I know about enteries of X and Z and they are not equal. All (X,Y and Z) follows properties of ABCD Chain matrix.

By knowing X and Z, I reached at point where all elements of Y are giving result 0. It shouldn't be so...

Re: Finding unknown matrix

- a*((323*b)/(10000*(a*d - b*c)) - (33*d)/(250*(a*d - b*c))) - c*((173*b)/(5000*(a*d - b*c)) - (71*d)/(500*(a*d - b*c))) = 0.1324

- b*((323*b)/(10000*(a*d - b*c)) - (33*d)/(250*(a*d - b*c))) - d*((173*b)/(5000*(a*d - b*c)) - (71*d)/(500*(a*d - b*c))) = 0.0298

a*((323*a)/(10000*(a*d - b*c)) - (33*c)/(250*(a*d - b*c))) + c*((173*a)/(5000*(a*d - b*c)) - (71*c)/(500*(a*d - b*c))) = 0.1526

b*((323*a)/(10000*(a*d - b*c)) - (33*c)/(250*(a*d - b*c))) + d*((173*a)/(5000*(a*d - b*c)) - (71*c)/(500*(a*d - b*c))) = 0.0342

Here is matlab computed result. Where a,b,c and d are y11,y12,y21 and y22 respectively.

Result suppose to be a = 0.9, b=0.10, c=0.11 and d=0.12, but i couldn't reach at this point