Hi , I'm totally lost on this question and answer attached . Please the full simplified working for both parts would be greatly appreciated . Thank you
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1. (r+1)! - (r-1)! = (r+1)r(r-1)! - (r-1)! Take (r-1)! as common factor and simplify. 2. Just expand : 2! - 0! + 3! - 1! + 4! - 2! + ...... (n-1)! - (n-2)! + n! - (n-2)! + (n+1)! - (n-1)! Cancel the terms ans add the rest.
Hi , thank you for part a) and the terms in b) but I am still struggling with how they arrive at the proof given after cancelling the terms . Any help would be appreciated . Thank you
The terms that are not cancelled are (n+1)! + n! - 1! -0! = n!(n+1+1) - 2. Hope this helps!
Originally Posted by minicooper58 Hi , I'm totally lost on this question and answer attached . Please the full simplified working for both parts would be greatly appreciated . Thank you Please show some of you own work on the problem before you post the question. This is not a homework answering service. -Dan
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