Can I get help with this question?

z^6 + (i+1)z^3 + i =0

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- Nov 24th 2012, 09:05 PMfrigidSolving a polynomial with complex numbers
Can I get help with this question?

z^6 + (i+1)z^3 + i =0 - Nov 24th 2012, 09:15 PMDevenoRe: Solving a polynomial with complex numbers
let w = z

^{3}, and use the quadratic formula to solve for w. then find the cube roots of w (there will be 3 for each solution you find for w, use demoivre). - Nov 24th 2012, 09:32 PMfrigidRe: Solving a polynomial with complex numbers
How do I use the quadratic formula on w^2 + (i +1)w+ i?

Would it be a=1,b=(i +1) and c=i? - Nov 24th 2012, 09:33 PMMarkFLRe: Solving a polynomial with complex numbers
Another approach:

I would factor as follows:

Can you proceed from here? - Nov 24th 2012, 09:45 PMfrigidRe: Solving a polynomial with complex numbers
yes thank you

- Nov 25th 2012, 01:01 AMDevenoRe: Solving a polynomial with complex numbers