
1 Attachment(s)
Matrix
Hello i got a problem!
ima decide a inverkar to this Matrix A=1 0 1 1 an it says clue ima set B= x y z tand decide x,y,z,t, for B shall be inverse to A.( its 2x2 the first 2 number are the number on top and the last 2 is at bottom idk what u say on english
Its a 2x2 Matrix sorry for not writing it with latex and sorry for My bad english.
So i did A•B and get C= 1x 1y, 1x+z, 1y+1t
idk why i did not write as t insted of having one before byt hope u guys did understand and looking forward to se all help

Re: Matrix
Hey Petrus.
Do you just want to find the inverted matrix of A given what is written in the attachment?
If the answer is yes, here is the Octave output for this problem:
>> A = [1, 0; 1, 1]
A =
1 0
1 1
>> inv(A)
ans =
1 0
1 1

Re: Matrix
suppose we want to invert:
$\displaystyle A = \begin{bmatrix}1&0\\1&1 \end{bmatrix}$
your clue says to set:
$\displaystyle B = \begin{bmatrix}x&y\\z&t \end{bmatrix}$.
so we calculate:
$\displaystyle AB = \begin{bmatrix} x&y\\zx&ty \end{bmatrix}$
if B is to be the inverse of A, we must have AB = I.
thus:
x = 1
y = 0
z  x = 0
t  y = 1
from z  1 = 0, we get z = 1.
from t  0 = 1, we get t = 1.
thus:
$\displaystyle A^{1} = B = \begin{bmatrix}1&0\\1&1 \end{bmatrix}$