by inspection:(3x - 2)(x - 3)

by method:

Step 1:

take the first terms times the last term. we get 18x^2

take the middle term, we have -11x

Step 2:

now think of two numbers that when multiplied gives 18x^2 and when added gives -11x

the numbers are: -2x and -9x

Step 3:

rewrite the quadratic, this time writing the middle term in terms of these two numbers, we get:

3x^2 - 9x - 2x + 6

Step 4:

factor by grouping:

we have 3x common to the first two terms and -2 common to the last two, so we get:

3x(x - 3) - 2(x - 3) ........factor out the common (x - 3)

= (x - 3)(3x - 2)