Let v be the column vector [1-i ; -3 ; -2i ; 0] and suppose v is an eigenvector of a Hermitian matrix M with eigenvalue -3. Calculate v^H M
What I did-
We know by definition Mv = -3v
Now, M = M^H because M is Hermitian. Then,
M^Hv = (v^H M)^H = conj(v^H M).
So, v^H M = conj(-3v)