I can see that it is true, but not sure how to prove it... Problem: Let G be a group of order 3, and let, e,a,b, be the three elements of G, where e is the identity of the group. SHOW that b must be the inverse of a. TIA
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Originally Posted by ginafara I can see that it is true, but not sure how to prove it... Problem: Let G be a group of order 3, and let, e,a,b, be the three elements of G, where e is the identity of the group. SHOW that b must be the inverse of a. TIA G is closed and each of its elements are distinct so is equal to e, a, or b. Well and , so we are left with . (Similarly for .) -Dan
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