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Math Help - Finding a differential function for a series

  1. #1
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    Finding a differential function for a series

    Given:
    f(x)=\sum^{\infty}_{n=1}\frac{2^n}{n}x^n
    x\in]-1,1[

    Find a differential equation f'(x), such that when you insert x in the equation, you get f'(x).

    Answer:
    f(x)=\frac{2}{1-2x}


    I'm not sure I entirely understand this question or how to start.
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  2. #2
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    Re: Finding a differential function for a series

    to start, compute f '(x) : You just have to derivate the general term of the series.
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