Let D:R[x]->R[x]be the differentiation operator D(f(x))=f'(x),prove that

e^tD(f(x))=f(x+t) for a real number t

i dont know how to construct to

proof ,what i wanna to use is lagranges interpolation

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- October 25th 2012, 04:21 PMcummings123321application of Lagranges interpolation
Let D:R[x]->R[x]be the differentiation operator D(f(x))=f'(x),prove that

e^tD(f(x))=f(x+t) for a real number t

i dont know how to construct to

proof ,what i wanna to use is lagranges interpolation - October 25th 2012, 04:48 PMHallsofIvyRe: application of Lagranges interpolation
I really don't know what you are asking. "Lagrange interpolation" has nothing to do with derivatives and "e^tD(f(x))=f(x+t) for a real number t" simply isn't true.