If I understand and as cosests. Then since 1 is identity, and . Thus, the problem reduces to finding a PROPER subring of a ring.Originally Posted by suedenation
Take any ring then the trivial subring satisfies these conditions.
Give an example of a ring R and a subring S of R so that R and S both have an
identity but 1S is not equal to 1R.
Any idea? I've spent almost an hour to do this, but still haven't got the answer.
The midterm is coming soon, hope someone can help me to solve this problem.
Thanks x 1000