Hi

Problem: a plane has got a straight line

(x,y,z)= (5+t,6-t,7+2t) and is parallell with

The line (x,y,z)= (3+t,5+t,6+t) determine the equation

Of the plane in normal form

We got two lines

I can write line1 as

(5,6,7) + t*(1,-1,2)

Means a point 1 and vector 1

The same applies for line2

(3,6,5) + t(1,1,1)

Point 2 and vector 2

I have a feeling I have to use Sarrus rule on this

Can someone show me how solve it?