Can R^3 have a basis of eigenvectors all of which have 0 in their first components, why or why not? Thank you in advance for your time.
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Originally Posted by nivek0078 Can R^3 have a basis of eigenvectors all of which have 0 in their first components, why or why not? Thank you in advance for your time. No, the rank of those three vectores is $\displaystyle <3.$
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