Thread: invertible and diagonalized matrix

Given the matrix A=[29,18][-50,-31] explain why there is no invertible matix P that diagonalizes A.

So I've solved for the eigenvalue and found that it is x2=[-3/5][1] and the A^-1 is [1/29,0][5/3,29/30]. Thank you in advance for your help.

Originally Posted by nivek0078

Given the matrix A=[29,18][-50,-31] explain why there is no invertible matix P that diagonalizes A.

The only eigen value of is (double) and That is, is not diagonalizable or equivalently, there is no invertible such that (diagonal).

Thank you for explaining that. It makes sense using the rank to solve it.