## Re: Can someone explain to me how you execute "Re" and "Im" in a formula?

Originally Posted by Plato
There is no $i$ in the imaginary part.

$\text{Im}(a+bi)=b$ NOT $bi$. I would mark that wrong.
Ah yes, so it's:

So it's
$Im((a+bi)(c+di))=bc+ad$

Which would give us:

$Im\left( \frac{-3+4i}{25}(\cos(t)+i\cdot\sin(t)) \right)=Im\left( \left( \frac{-3}{25} + \frac{4}{25} \right) \left( \cos(t) + \cdot \sin(t)\right) \right)=\frac{4}{25}\cdot \cos(t) + \frac{-3}{25}\cdot \sin(t)$