At what time between 2 and 3 o'clock are the hands of the clock opposite each other?

please help me on this... kind of dont understand the phrase "the hands of the clock opposite each other" .i need your guide on this.

thanks

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- Sep 7th 2012, 06:08 AMrcsClock problem
At what time between 2 and 3 o'clock are the hands of the clock opposite each other?

please help me on this... kind of dont understand the phrase "*the hands of the clock opposite each other" .*i need your guide on this.

thanks - Sep 7th 2012, 06:44 AMProve ItRe: Clock problem
- Sep 7th 2012, 07:04 AMrcsRe: Clock problem
- Sep 7th 2012, 07:17 AMProve ItRe: Clock problem
Here's how I would try to do it. In one hour, the hour hand will move from the 2 to the 3, and the minute hand will do a complete rotation from the 12 back to the 12. It should be obvious that the minute hand needs to at least get to the 8 (where it will be opposite the 2) and can not get to the 9 (opposite the 3).

To get to the 8 takes 40 minutes. 40 minutes is 2/3 of an hour, so the hour hand will be 2/3 of the way between 2 and 3.

Now think "every minute, the hour hand will move 1/60 of the way between 2 and 3, and the minute hand will move 1/5 of the way between 8 and 9".

See if you can continue. - Sep 7th 2012, 07:45 AMemakarovRe: Clock problem
Attachment 24725

I suggest denoting by x the fraction of the hour that passed after 2 o'clock. Thus, $\displaystyle \frac{8}{12}<x<\frac{9}{12}$. - Sep 8th 2012, 05:15 AMrcsRe: Clock problem
thanks Sir ProveIt ....