This thread may give you some ideas.
This thread may give you some ideas.
40 quarts of milk containing 40% butter fat has (40)(.4)= 16 quarts of butter fat. If the total liquid, after adding water is "V", then it will be "3% butter fat" if .03V= 16. Can you solve that for V? How much water would you need to add to get from 40 quarts up to V quarts?
hi friends,
using allegation formula
40%-3% = 37% : 3%-0%=3%
=> 37:3 = water:milk
=> 37:3 = x:40
=> x= (37*40)/3
water:milk = (40-3)/(3-0)
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all the best!!
Hello, rcs!
I'll give you my approach to these Mixture Problems.
Water is to be added to 40 quarts of milk containing 40% of butterfat
so as to produce a mixture containing 3% butterfat.
How many quarts of water must be added?
Since we are adding water, we will consider the amount of water at each stage.
We begin with 40 quarts which is 60% water.
It contains: . quarts of water.
We add quarts of water.
Then the mixture contains quarts of water. .[1]
Let's look at the problem again:
We begin with 40 quarts of milk and add quarts of water.
The mixture contains quarts and is supposed to be 97% water.
That is, it contains: . quarts of water. .[2]
We just described the final amount of water in two ways.
There is our equation! . . . .
Can you finish up now?
The answer is quarts of water.
sir Soroban how did you get the 0.60 x 40% ... there is no 0.60 in the problem if this happens to the problem
Water is to be added to 40 quarts of milk containing 4% of butterfat
so as to produce a mixture containing 3% butterfat.
How many quarts of water must be added?
what happens to the mixture ... im confused of the solution.