# mixture problem:

• Sep 7th 2012, 07:05 AM
rcs
mixture problem:
If water is to be added to 40 quarts of milk containing 40% of butter fat so as to produce a mixture containing 3% butter fat. How many quarts of water must be added?

need your help on this guys.

thanks
• Sep 7th 2012, 07:21 AM
emakarov
Re: mixture problem:
This thread may give you some ideas.
• Sep 7th 2012, 08:06 AM
HallsofIvy
Re: mixture problem:
Quote:

Originally Posted by rcs
If water is to be added to 40 quarts of milk containing 40% of butter fat so as to produce a mixture containing 3% butter fat. How many quarts of water must be added?

need your help on this guys.

thanks

40 quarts of milk containing 40% butter fat has (40)(.4)= 16 quarts of butter fat. If the total liquid, after adding water is "V", then it will be "3% butter fat" if .03V= 16. Can you solve that for V? How much water would you need to add to get from 40 quarts up to V quarts?
• Sep 7th 2012, 10:31 AM
qchris
Re: mixture problem:
hi friends,

using allegation formula

40%-3% = 37% : 3%-0%=3%

=> 37:3 = water:milk
=> 37:3 = x:40
=> x= (37*40)/3

water:milk = (40-3)/(3-0)

for more help on alligations and mixtures you can visit sites like numbertwo.com, Alligation or Mixture | Aptitude Question and Answers | Interview Questions with Answers
all the best!!
• Sep 7th 2012, 03:01 PM
Soroban
Re: mixture problem:
Hello, rcs!

I'll give you my approach to these Mixture Problems.

Quote:

Water is to be added to 40 quarts of milk containing 40% of butterfat
so as to produce a mixture containing 3% butterfat.
How many quarts of water must be added?

Since we are adding water, we will consider the amount of water at each stage.

We begin with 40 quarts which is 60% water.
It contains: . $0.60\times 40 \,=\,24$ quarts of water.

We add $x$ quarts of water.

Then the mixture contains $x + 24$ quarts of water. .[1]

Let's look at the problem again:

We begin with 40 quarts of milk and add $x$ quarts of water.
The mixture contains $x+40$ quarts and is supposed to be 97% water.
That is, it contains: . $0.97(x+40)$ quarts of water. .[2]

We just described the final amount of water in two ways.

There is our equation! . . . . $x+24 \;=\;0.97(x+40)$

Can you finish up now?

The answer is $493\tfrac{1}{3}$ quarts of water.
• Sep 8th 2012, 06:07 AM
rcs
Re: mixture problem:
as i have seen the answer of from the book where this problem was taken, is 13 1/3 quarts of water
• Sep 8th 2012, 06:52 AM
HallsofIvy
Re: mixture problem:
Quote:

Originally Posted by rcs
as i have seen the answer of from the book where this problem was taken, is 13 1/3 quarts of water

Then I suggest you go to your teacher and ask him or here for help. "13 and 1/3 quarts" is NOT the correct answer to the problem you posed.
• Sep 8th 2012, 11:23 PM
rcs
Re: mixture problem:
HallsofIvy = queer
• Sep 9th 2012, 05:27 AM
rcs
Re: mixture problem:
sir Soroban how did you get the 0.60 x 40% ... there is no 0.60 in the problem if this happens to the problem

Water is to be added to 40 quarts of milk containing 4% of butterfat
so as to produce a mixture containing 3% butterfat.
How many quarts of water must be added?

what happens to the mixture ... im confused of the solution.