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Math Help - Rearranging an algebraic equation

  1. #1
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    Rearranging an algebraic equation

    Having some difficulty making q the subject:

    ((a-c)/b(2+vj)-(q/2+vj) = ((a-c)/b)-q(2+vi)

    Any help would be appreciated.
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  2. #2
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    Re: Rearranging an algebraic equation

    Quote Originally Posted by SergioYaya View Post
    Having some difficulty making q the subject:

    ((a-c)/b(2+vj)-(q/2+vj) = ((a-c)/b)-q(2+vi)

    Any help would be appreciated.
    Separate everything involving q from every thing NOT involving q:
    [(a-c)/(b(2+vj))]- q/2- [vj]= [(a- c)/b]- (2+vi)q

    Get everything involving q on the left side, everything not involving q on the right side:
    -q/2- (2+vi)q= (a-c)b+ vj- (a-c)/(b(2+vj))

    Factor q out on the left:
    (-1/2- 2+vi)q= (a-c)b+ vj- (a-c)/(b(2+vj))

    Divide both sides by -1/2- 2+ vi:
    q= [(a-c)b+ vj-(a-c)/(b(2+vj))]/(-1/2- 2+ vi)
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  3. #3
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    Re: Rearranging an algebraic equation

    Thank you for the reply, however, I still do not fully understand how you came to this conclusion. My notes tell me that a simpler version of this problem:
    ((a-c)/b)-q(2+v)=((a-c)/b(2+v))-(q/2+V) equates to q*= (a-c)/b(3+v) and I just don't understand how this is possible.
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  4. #4
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    Re: Rearranging an algebraic equation

    Quote Originally Posted by SergioYaya View Post
    Having some difficulty making q the subject:

    ((a-c)/b(2+vj)-(q/2+vj) = ((a-c)/b)-q(2+vi)

    Any help would be appreciated.
    what are a,b,c,i,j and q?
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  5. #5
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    Re: Rearranging an algebraic equation

    q is quantity, c is costs, a and b form part of pricing, vi and vj are conjectural variation terms so they are all simply letters which must be rearranged.
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