1. Subtract 9 from both sides of the equation:
Divide both sides by 5 to get .
2. is done the same way.
3. is a little unclear -- do you mean or ?
4. Expand both sides to get . Bring all the terms to one side, solve for .
Hello,
I am in eight grade Math Honors and I would like some help on the following questions:
1. 5x + 9 = 2
2. 7 - 6d = 3
3. 1/3y - 2 = 4
4. 7 (10-3w) = 5(15 -4w)
This may look easy for you guys, but I don't have a lot of time and I don't know which place to post this.
But PLEASE PLEASE HELP! Can you explain how to do it? Please don't just give the answers, I need to know how to solve it.
Thanks, Help is appreciated.
1. Subtract 9 from both sides of the equation:
Divide both sides by 5 to get .
2. is done the same way.
3. is a little unclear -- do you mean or ?
4. Expand both sides to get . Bring all the terms to one side, solve for .
no, that is incorrect on the second one. you should always check your work:
if d = -4/6, then:
7 - 6d = 7 - 6(-4/6) = 7 + 4 = 11, which is not 3.
i would proceed as follows (since you appear to have trouble with "signs"):
7 - 6d = 3
7 - 6d + 6d = 3 + 6d
7 + 0 = 3 + 6d
7 = 3 + 6d
7 = 6d + 3
7 - 3 = 6d + 3 - 3
...can you continue?
by the way, this *is* the wrong section, this is "pre-college algebra" not "college algebra" (as you might have guessed from being in the 8th grade, which is not college, hmm?)