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Hello,
I am in eight grade Math Honors and I would like some help on the following questions:
1. 5x + 9 = 2
2. 7 - 6d = 3
3. 1/3y - 2 = 4
4. 7 (10-3w) = 5(15 -4w)
This may look easy for you guys, but I don't have a lot of time and I don't know which place to post this.
But PLEASE PLEASE HELP! Can you explain how to do it? Please don't just give the answers, I need to know how to solve it.
Thanks, Help is appreciated.
1. Subtract 9 from both sides of the equation:
Divide both sides by 5 to get.
2. is done the same way.
3. is a little unclear -- do you meanor
?
4. Expand both sides to get. Bring all the
terms to one side, solve for
Thanks. For the second one, if it is done the same way as the first one, would the answer be: D = -4/6? Also, the third one is the first one on your post. 1/3y - 2 = 4, and the two is not under the one.
no, that is incorrect on the second one. you should always check your work:Quote:
Originally Posted by AbhiKap
if d = -4/6, then:
7 - 6d = 7 - 6(-4/6) = 7 + 4 = 11, which is not 3.
i would proceed as follows (since you appear to have trouble with "signs"):
7 - 6d = 3
7 - 6d + 6d = 3 + 6d
7 + 0 = 3 + 6d
7 = 3 + 6d
7 = 6d + 3
7 - 3 = 6d + 3 - 3
...can you continue?
by the way, this *is* the wrong section, this is "pre-college algebra" not "college algebra" (as you might have guessed from being in the 8th grade, which is not college, hmm?)
Yeah, second one's not -4/6. Apparently you put this in the "advanced algebra" forum. Algebra can be waaaay more abstract than what you're learning right now.
As mentioned before, I am aware of the fact that this is in the wrong section. However, the reason I put it here is because I couldn't find a Super Basic Algebra section, if there is one.
Deveno, I don't get your last steps, can you explain them please?