Please prove the following laws
a.(bxc)= b.(cxa)=c.(bxa)
ax(bxc)=b(a.c) -c(a.b)
(axb).(cxd)= (a.c)(b.d) -(a.d)(b.c)
ax(bxc) +bx(cxa) + cx(axb) = 0
(axb)x(cxd) = b(a.(cxd))-a.(b.(cxd))
= c(a.(bxd)) - d(a.(bxc)
(axb).((bxc)x(cxa))= (a.(bxc))^2
thank you!