In each case compute f o g (x) where

**arsenal12345** · August 5th 2012, 03:33 AM

f(x) = 2x + 3 and g(x) = x^2 − 1.

fog(x)= 2(x^2-1)+3
gof(x) = 2x^2+1

gof (x) dosent equal to fog(x)

f(x) = x^2 − 1 and g(x) = 2x + 3.

fog ( x) = x(2x+3)^2-1
gof(x)= 4x^2+12x+8

gof (x) dosent equal to fog(x)

are thses right with proper working ?

if not can some1 show me the answear and the proper working
cheers

**Prove It** · August 5th 2012, 03:37 AM

Originally Posted by arsenal12345

f(x) = 2x + 3 and g(x) = x^2 − 1.

fog(x)= 2(x^2-1)+3
gof(x) = 2x^2+1

gof (x) dosent equal to fog(x)

f(x) = x^2 − 1 and g(x) = 2x + 3.

fog ( x) = x(2x+3)^2-1
gof(x)= 4x^2+12x+8

gof (x) dosent equal to fog(x)

are thses right with proper working ?

if not can some1 show me the answear and the proper working
cheers

In question 1, $\displaystyle \begin{align*} f \circ g (x) \end{align*}$ is correct, $\displaystyle \begin{align*} g \circ f(x) \end{align*}$ is not.

**arsenal12345** · August 5th 2012, 04:03 AM

Originally Posted by Prove It

In question 1, $\displaystyle \begin{align*} f \circ g (x) \end{align*}$ is correct, $\displaystyle \begin{align*} g \circ f(x) \end{align*}$ is not.

is it 4x^3 + 9x+12 - 1 ??

fog (x) dosent eqauel to gof (x)

**Prove It** · August 5th 2012, 04:56 AM

Originally Posted by arsenal12345

is it 4x^3 + 9x+12 - 1 ??

fog (x) dosent eqauel to gof (x)

No.

$\displaystyle \begin{align*} g \circ f(x) &= g\left(f(x)\right) \\ &= \left(2x + 3\right)^2 - 1 \\ &= 4x^2 + 12x + 9 - 1 \\ &= 4x^2 + 12x + 8 \end{align*}$

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