At what point on the curve xy = ( 1 - x - y)^2 is the tangent line parallel to the x - axis

need your assistance here guys...

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- July 31st 2012, 12:36 AMrcsthe point tangent to line
At what point on the curve xy = ( 1 - x - y)^2 is the tangent line parallel to the x - axis

need your assistance here guys... - July 31st 2012, 02:55 AMProve ItRe: the point tangent to line
- July 31st 2012, 04:49 AMrcsRe: the point tangent to line
Sir that term i coudnt answer ... im sorry i couldnt get the hint :(

- July 31st 2012, 05:35 AMPlatoRe: the point tangent to line
- July 31st 2012, 07:04 AMHallsofIvyRe: the point tangent to line
If you do not know what "gradient' (American English: "slope") of a line is, you should not be attempting a problem like this. Finding the derivative is far more advanced that the 'slope' or 'gradient' of a line.

- July 31st 2012, 11:08 AMrichard1234Re: the point tangent to line
- July 31st 2012, 05:36 PMrcsRe: the point tangent to line
i guess basic for u but im trying to know all these things sir :(

- July 31st 2012, 06:03 PMPlatoRe: the point tangent to line
- July 31st 2012, 06:29 PMrichard1234Re: the point tangent to line
- July 31st 2012, 06:33 PMrichard1234Re: the point tangent to line
The solution would involve differentiating both sides with respect to x:

(using chain rule)

Then set dy/dx = 0. - July 31st 2012, 06:59 PMrcsRe: the point tangent to line
thank you Plato. You have a very positive statement :). Keep it up!