At what point on the curve xy = ( 1 - x - y)^2 is the tangent line parallel to the x - axis
need your assistance here guys...
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At what point on the curve xy = ( 1 - x - y)^2 is the tangent line parallel to the x - axis
need your assistance here guys...
What is the gradient of the x axis? Hint: It's horizontal...Quote:
Originally Posted by rcs
Sir that term i coudnt answer ... im sorry i couldnt get the hint :(
Quote:
Originally Posted by rcs
now find a point
so that
.
If you do not know what "gradient' (American English: "slope") of a line is, you should not be attempting a problem like this. Finding the derivative is far more advanced that the 'slope' or 'gradient' of a line.
You've posted a lot of algebra questions on this forum, and this question might be too advanced for you. How much calculus do you know?Quote:
Originally Posted by rcs
i guess basic for u but im trying to know all these things sir :(
What the hell does that mean?Quote:
Originally Posted by rcs
That is not even a well formed English sentence
If you cannot post an proper statement or question then post nothing !
I don't think you're quite ready for derivatives and calculus, especially since you've been posting elementary algebra questions. You need to be proficient in algebra to do well in calculus.Quote:
Originally Posted by rcs
The solution would involve differentiating both sides with respect to x:
(using chain rule)
Then set dy/dx = 0.
thank you Plato. You have a very positive statement :). Keep it up!