Hi!

I've a problem, I have to find a vector v=[vx vy]' (column) such that:

y*v<x.

where y=[y1 y2] (row) and x,y1,y2,vx,vy are a real scalar.

Does anyone know an analytic solution?

thanks

Michele

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- June 29th 2012, 03:58 AM #1

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- June 29th 2012, 06:23 AM #2

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## Re: y*v<x

Any vector?

Your equation can be written as vx*y1 + vy*y2 < x.

There are many solutions (unless y1=y2=0 and x<=0). In the general case, you can freely choose one component, for example vx=0. The remaining inequality vy*y2<x is satisfied for vy = x/y2 -1, assuming y2 !=0.

- June 29th 2012, 06:42 AM #3

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