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Math Help - y*v<x

  1. #1
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    y*v<x

    Hi!
    I've a problem, I have to find a vector v=[vx vy]' (column) such that:
    y*v<x.
    where y=[y1 y2] (row) and x,y1,y2,vx,vy are a real scalar.


    Does anyone know an analytic solution?


    thanks

    Michele
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  2. #2
    mfb
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    Re: y*v<x

    Any vector?
    Your equation can be written as vx*y1 + vy*y2 < x.
    There are many solutions (unless y1=y2=0 and x<=0). In the general case, you can freely choose one component, for example vx=0. The remaining inequality vy*y2<x is satisfied for vy = x/y2 -1, assuming y2 !=0.
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  3. #3
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    Re: y*v<x

    Quote Originally Posted by Aliekor View Post
    x,y1,y2,vx,vy are a real scalar.
    ...So x can be x<=0... i can assume y!=0
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