Results 1 to 2 of 2

Math Help - How to solve this three-variable quadratic Diophantine equation?

  1. #1
    Newbie
    Joined
    Jun 2012
    From
    Earth
    Posts
    1

    How to solve this three-variable quadratic Diophantine equation?

    I have the following quadratic diophantine of three variables: (4x^2 + 1 )( 4y^2 + 1 ) = (4z^2 + 1) but cannot find a good algorithm or method for finding solutions. Any advice would be appreciated.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Senior Member DeMath's Avatar
    Joined
    Nov 2008
    From
    Moscow
    Posts
    473
    Thanks
    5

    Re: How to solve this three-variable quadratic Diophantine equation?

    Maybe you should try these replacements: 4x^2+1=a and 4y^2+1=b.
    Last edited by DeMath; June 27th 2012 at 03:07 AM.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 0
    Last Post: September 28th 2011, 01:07 AM
  2. Extra Solutions of a Quadratic Diophantine Equation
    Posted in the Number Theory Forum
    Replies: 3
    Last Post: May 21st 2011, 05:20 AM
  3. Quadratic Diophantine equation
    Posted in the Number Theory Forum
    Replies: 1
    Last Post: January 23rd 2011, 11:43 AM
  4. Replies: 1
    Last Post: March 17th 2010, 01:43 PM
  5. How does one solve a quadratic Diophantine equation?
    Posted in the Advanced Algebra Forum
    Replies: 1
    Last Post: November 17th 2009, 04:46 AM

Search Tags


/mathhelpforum @mathhelpforum