Well now you can distribute getting: (x'x'z+y'x'z+z'x'z) = x'z + y'x'z + x'
hey
i've got this expression:
[x'+(yz)'](x+z')'
and i'm supposed to simplify it. I've gotten this far:
[x' + y' + z')(x'z)
I have no clue on what to do next. i've not been taught how to do this and i'm expected to hand in an assignment today about this.
any sort of help will be much appreciated.
thanks