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Math Help - boolean algebra to simplify

  1. #1
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    boolean algebra to simplify

    hey
    i've got this expression:
    [x'+(yz)'](x+z')'
    and i'm supposed to simplify it. I've gotten this far:
    [x' + y' + z')(x'z)

    I have no clue on what to do next. i've not been taught how to do this and i'm expected to hand in an assignment today about this.
    any sort of help will be much appreciated.

    thanks
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  2. #2
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    Re: boolean algebra to simplify

    Well now you can distribute getting: (x'x'z+y'x'z+z'x'z) = x'z + y'x'z + x'
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  3. #3
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    Re: boolean algebra to simplify

    cheers. helped me out
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  4. #4
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    Re: boolean algebra to simplify

    Quote Originally Posted by wsldam View Post
    Well now you can distribute getting: (x'x'z+y'x'z+z'x'z) = x'z + y'x'z + x'
    zz' = 0 (i.e., always false), so we have x'z + y'x'z, not x'z + y'x'z + x'. Further, x'z + y'x'z = (x' + x'y')z = x'z because x' + x'y' = x'(1 + y') = x'1 = x'.
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  5. #5
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    Re: boolean algebra to simplify

    i got that when i finished off
    thanks though
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