# Thread: boolean algebra to simplify

1. ## boolean algebra to simplify

hey
i've got this expression:
[x'+(yz)'](x+z')'
and i'm supposed to simplify it. I've gotten this far:
[x' + y' + z')(x'z)

I have no clue on what to do next. i've not been taught how to do this and i'm expected to hand in an assignment today about this.
any sort of help will be much appreciated.

thanks

2. ## Re: boolean algebra to simplify

Well now you can distribute getting: (x'x'z+y'x'z+z'x'z) = x'z + y'x'z + x'

3. ## Re: boolean algebra to simplify

cheers. helped me out

4. ## Re: boolean algebra to simplify

Originally Posted by wsldam
Well now you can distribute getting: (x'x'z+y'x'z+z'x'z) = x'z + y'x'z + x'
zz' = 0 (i.e., always false), so we have x'z + y'x'z, not x'z + y'x'z + x'. Further, x'z + y'x'z = (x' + x'y')z = x'z because x' + x'y' = x'(1 + y') = x'1 = x'.

5. ## Re: boolean algebra to simplify

i got that when i finished off
thanks though