changing the log expression to equal expression with exponent
does ln 1/e^6 = -6
convert into 1/e^6 = e ^-6 ???
Re: changing the log expression to equal expression with exponent
Re: changing the log expression to equal expression with exponent
Quote:
Originally Posted by
blondedude092 
does ln 1/e^6 = -6
convert into 1/e^6 = e ^-6 ???
Assuming you were trying to write } \end{align*})
, yes you are correct :)
Re: changing the log expression to equal expression with exponent
In general, ln(a)= b is the same as (converts into) 
so, in particular, = -6)
, 
because 
and b= -6.
Re: changing the log expression to equal expression with exponent
As an alternative we could say ln1/e^6 = ln1-lne^6 =0-6 = -6
Re: changing the log expression to equal expression with exponent
Quote:
Originally Posted by
biffboy As an alternative we could say ln1/e^6 = ln1-lne^6 =0-6 = -6
I don't want to pick at you but to be exact
ln1/e^6 = 0
