System of equations using mod

If i have two equations ,

11a+b(mod26)=17

&

22a+b(mod26)=22

How do i begin to solve for a and b? Ive been trying to make vectors out of them and i get for a=11/5, but this doesn't sound right, i think i should be getting whole numbers shouldn't i?

Re: System of equations using mod

$\displaystyle 22a+b \equiv 22$ (mod 26)

$\displaystyle 11a+b \equiv 17$ (mod 26)

$\displaystyle \Rightarrow 11a \equiv 5$(mod 26)

$\displaystyle \Rightarrow a \equiv 5.11^{-1}$(mod 26)

$\displaystyle 11^{-1}=19$ Since $\displaystyle 11.19 \equiv 1 $ (mod 26)

$\displaystyle \Rightarrow a \equiv 5.19$(mod 26)

$\displaystyle \Rightarrow a \equiv 17$ (mod 26)