Re: newton-raphson formula

I guess your equation is $\displaystyle f(x)=2xln(x)-1$ right?

then, just use the definition,

$\displaystyle x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)}$

$\displaystyle f'(x)=2+2ln(x)$

substitute and simplify

Re: newton-raphson formula

Yes, using the formula x(n+1) = x(n) - f(x) /f'(x) is the way to go

f(x) = 2x(n) ln(x(n)) - 1

f'(x) = 2(ln(x(n)+1)

substitute these into the formula, multiply terms out & cancel those terms at the top that you can (should be the 2x(n) ln(x(n)) ones)

At least that's how I did it.

Re: newton-raphson formula

thank you chaps.i will give it a go : )