I've got one of my own:
Let G be a semi-group. (That means G is a set with an associative binary operation on it.) Assume further that in G:
1) There exists a left identity e such that ea=a for all a in G and
2) For all a in G there exists a right inverse such that .
The question: Is G a group?
My answer is "no" but I don't have anything like a proof. What I'm stuck on is the uniqueness of e...I can prove that if there is a d such that da=a for all a in G then , but I can't prove d=e or d is not equal to e...all I have is there doesn't appear to be a contradiction in assuming that more than one left identity exists. What would really be nice is if there were an example showing that G is not a group. (Or, alternately, a proof that it is.)
Any suggestions? Thanks!