If it were in Q then the polynomial would be p(x) = x - π^2, but I don't know if being over Q(π^3) changes that. I think that when you compare the fields you get degree 1, but again, I'm not completely sure.

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- Mar 26th 2012, 10:11 AMlteece89Find the minimal polynomial for a = π^2 over Q(π^3)
If it were in Q then the polynomial would be p(x) = x - π^2, but I don't know if being over Q(π^3) changes that. I think that when you compare the fields you get degree 1, but again, I'm not completely sure.

- Mar 26th 2012, 10:33 AMSylvia104Re: Find the minimal polynomial for a=π^2 over Q(π^3)
If the extension is $\displaystyle \mathbb Q(\pi)/\mathbb Q\left(\pi^3\right)$ the minimal polynomial is $\displaystyle x^3-\pi^6.$

- Mar 26th 2012, 11:54 AMlteece89Re: Find the minimal polynomial for a = π^2 over Q(π^3)
Is this because the minimal polynomial needs to be degree three?

- Mar 26th 2012, 01:40 PMSylvia104Re: Find the minimal polynomial for a=π^2 over Q(π^3)
The minimal polynomial here is the monic polynomial $\displaystyle f(x)$

*of minimal degree*with coefficients in $\displaystyle \mathbb Q\left(\pi^3\right)$ such that $\displaystyle f\left(\pi^2\right)=0.$ If $\displaystyle f(x)$ has degree $\displaystyle 1$ or $\displaystyle 2,$ $\displaystyle f\left(\pi^2\right)$ is of the form $\displaystyle a_0+\pi^2$ or $\displaystyle a_0+a_1\pi^2+\pi^4,$ where $\displaystyle a_0,a_1\in\mathbb Q\left(\pi^3\right);$ clearly these cannot be $\displaystyle 0.$