Hey guys, I'm having a lot of trouble with this problem:

5x + 4y = 29

y + z - w = -2

5x + z = 23

y - z + w = 4

Yeah, I don't even know where to start on this one, so any kind of help would be greatly appreciated.

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- September 25th 2007, 05:14 PMasdfasdfLinear Equations in 4 variables..
Hey guys, I'm having a lot of trouble with this problem:

5x + 4y = 29

y + z - w = -2

5x + z = 23

y - z + w = 4

Yeah, I don't even know where to start on this one, so any kind of help would be greatly appreciated. - September 25th 2007, 05:18 PMJhevon
- September 25th 2007, 05:28 PMasdfasdf
- September 25th 2007, 05:32 PMJhevon
oh. well in that case. you are to use the equations to try and eliminate some variables so you can solve for others. similar to what you would do if it were just 2 simultaneous equations (you can solve such systems right?).

for example, note that we can solve for y by adding the second and fourth equations - September 25th 2007, 05:49 PMasdfasdf
yes. in the past I've dealt with solving these types of equations in 2 variables. However, although that is really easy, for some reason I just can't find the relationship between solving an equation with only 2 variables to solving an equation like this one..I understand that I can solve for y in the 2nd and 4th equations, and the answer would be y = 1, but where would I go from there?

- September 25th 2007, 05:59 PMJhevon
well, one way would be to replace y with one in all the other equations, so now you only have 3 variables to worry about.

another way would be to continue like nothing happened, and try to add/subtract other sets of equations to eliminate other variables. sometimes you won't be left with just one variable as you were with y. but you can add/subtract the new equations you form to eliminate other variables until you are left with one. - September 25th 2007, 06:35 PMasdfasdf