Addition of complex conjugates by induction

prove that overbar/(z1 + z2 + .... + zn) = overbar(z1) + overbar(z2) + .... +overbar(zn)

I showed true for n = 2 already

I then assumed true for n = k and wrote out the induction hypothesis

Then of course I need to show true for n = k + 1 and substitute the induction hypothesis in. So I came out with

overbar(z1 + z2 + .... + zn + zn+1) = overbar/(z1 + z2 + .... + zn) + overbar(zn+1)

I know I'm close, and I'm sure it's something simple that I'm missing but I don't know what to do next.

Any help?

Re: Addition of complex conjugates by induction

Quote:

Originally Posted by

**Johngalt13** prove that overbar/(z1 + z2 + .... + zn) = overbar(z1) + overbar(z2) + .... +overbar(zn)

I showed true for n = 2 already

I then assumed true for n = k and wrote out the induction hypothesis

Then of course I need to show true for n = k + 1 and substitute the induction hypothesis in. So I came out with

$\displaystyle \overline{(z_1 + z_2 + .... + z_n + z_{n+1})} = \overline{(z_1 + z_2 + .... + z_n)} + \overline{z_{n+1}}$

You are right there.

You know it works for two numbers as well as $\displaystyle \overline{(z_1 + z_2 + .... + z_n)}$

Re: Addition of complex conjugates by induction

Quote:

Originally Posted by

**Plato** You are right there.

You know it works for two numbers as well as $\displaystyle \overline{(z_1 + z_2 + .... + z_n)}$

Edit:Nevermind I got it, thanks that helped!