you have to split the denominator in (s-2-4i)(s-2+4i)
Hi I'm trying to work out the inverse Laplace transform of 4/[(s-2)^2 + 16]
Could anyone help please? I have tried factorising the denominator part which can also be written as s^2 - 4s + 20 but aren't there only surd factors to satisfy this? I think I'm better leaving it in its original completed square form but I'm if I do I'm not sure how to go about doing the partial fractions stage to find a standard inverse transform...