[SOLVED] P matrix of Jordan Form

Find P such that, $P^{-1}AP=J$

$A=\begin{bmatrix}0&1&1&0&1\\0&0&1&1&1\\0&0&0&0&0\\ 0&0&0&0&0\\0&0&0&0&0\end{bmatrix}$

$\lambda^5=0$

Minimal Polynomial is $\lambda^3-0$ .

The Jordan Blocks are:

$\left\{\begin{bmatrix}0&1&0\\0&0&1\\0&0&0\end{bmat rix} , \ \begin{bmatrix}0\end{bmatrix}, \ \begin{bmatrix}0\end{bmatrix}\right\}$

Eigenvectors:

$\left\{\begin{bmatrix}1\\0\\0\\0\\0\end{bmatrix}, \ \begin{bmatrix}0\\0\\-1\\0\\1\end{bmatrix}, \ \begin{bmatrix}0\\1\\-1\\1\\0\end{bmatrix}\right\}$

How do I find the other 2 vectors to complete my P matrix?

I have no idea why the LaTex is screwy on the first Jordan Block matrix but it is typed in correctly.