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Given A= [1,1,1] and B=[2,-1,0] Find vector C which is Coplanar With A and B and perpendicular to A My solution:1. The triple product for ll those three vectors should equal 0 (i.e. A.(BXC)= 0)2. A.C=0 (i.e using Dot product)So, I've 2 equations and i can't get C can anybody help, Urgently please?
What aboutQuote:
Originally Posted by ahmedzoro10
more explain,please
No. You have to do somethings for yourself.Quote:
Originally Posted by ahmedzoro10
Have you done those operations.
Is the result coplanar with A & B?
Is it perpendicular to A?
I've already 2 equations which consist of x,y and Z for C
First, A, B and C are already coplanar so I got the first equation which is x+2y-3z=0
then, A and C are coplanar so i got the sec. equation which is x+y+z=0
and I can't go on :(
A and C are orthogonal*
yes there're
how did you get this formula?!
yes they're!!
how did you get this formula?!
This well known triple vector product:Quote:
Originally Posted by ahmedzoro10
.
That is a vector which is coplanar withand is perpendicular to
.
yes i got it thanks :)