Given a set X, prove that there exists a free R-module F with a basis B for which there is a

bijection ϕ : B → X.

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- December 4th 2011, 10:02 AMjcir2826Modules
Given a set X, prove that there exists a free R-module F with a basis B for which there is a

bijection ϕ : B → X. - December 4th 2011, 10:34 AMDrexel28Re: Modules
- December 4th 2011, 08:54 PMjcir2826Re: Modules
So I am just missing to show that there is a bijection from this natural basis to the free module direct summand R and X?

- December 4th 2011, 09:19 PMDrexel28Re: Modules