Hi, assuming that a simple non-abelian group $\displaystyle $G$$ of order 60 can be embedded in $\displaystyle $S_6$$, I want to prove that $\displaystyle $G$$ cannot contain an odd permutation and is therefore a subgroup of $\displaystyle $A_6$$ (and then from that I can deduce that as it is order 60 it is $\displaystyle $A_5$$). How would I go about showing this?