If you multiply it out, you'll get that q(x,y,z) is a polynomial in the three variables. You want to find the extrema in 3-space subject to the constraint x^2+y^2+z^2=1. Check out "Lagrange multipliers" for a method.
Let A denote the matrix
A=
1 1 -12and define the quadratic
-1 1 0
0 0 2
q(x):= <x,Ax>
where<> defines the inner product
Determine the supremum and infimum of q(x) over all unitx vectors x
By definiton we know that the infinum and supremum are interrelated by being the smallest and largest numbers that are less than all elements or greater than all elements in a set t.
I am a bit confused since x is only unit so its range of values should not be infinite (so my logic tells me) and this is the time we use the infimum and supremum.
I am having trouble starting the problem.
Thank you very much for any help,
-Carlos
If you multiply it out, you'll get that q(x,y,z) is a polynomial in the three variables. You want to find the extrema in 3-space subject to the constraint x^2+y^2+z^2=1. Check out "Lagrange multipliers" for a method.