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Another hw question i'm having trouble with (Headbang) How would I go about doing it?

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- October 24th 2011, 12:47 AMkmjtFor what values of k does A^-1 exist?
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Another hw question i'm having trouble with (Headbang) How would I go about doing it? - October 24th 2011, 12:50 AMProve ItRe: For what values of k does A^-1 exist?
- October 24th 2011, 01:05 AMkmjtRe: For what values of k does A^-1 exist?
Normally I am good with inverses and determinants however the letters are confusing me. All the k in there is what confuses me, how would I approach it?

- October 24th 2011, 01:20 AMProve ItRe: For what values of k does A^-1 exist?
- October 24th 2011, 01:20 AMDevenoRe: For what values of k does A^-1 exist?
det(A) = (k)(4)(k) + (k)(k^2)(0) + (0)(k^2)(k) - (0)(4)(0) - (k^2)(k)(k) - (k)(k)(k^2)

you do the rest. - October 24th 2011, 03:10 AMkmjtRe: For what values of k does A^-1 exist?
I calculated det(A) = -2k^4 + 4k^2

But what would I do from there? sorry - October 24th 2011, 03:24 AMProve ItRe: For what values of k does A^-1 exist?
- October 24th 2011, 03:28 AMDevenoRe: For what values of k does A^-1 exist?
you might find it helpful to factor 4k^2 - 2k^4 = 0 as

2k^2(2 - k^2) = 0, first. this polynomial in k has 3 distinct roots, which we cannot allow k to be, if our matrix is to be invertible.