Originally Posted by

**Paymemoney** Hi

The following question ask to find eigenvector:

$\displaystyle \left[ \begin{matrix} 3 & 2 & 0 \\ 2 & 3 & 0 \\ 0 & 0 & 1 \end{matrix} \right]$

Now the answer i got was correct according to book, however i don't understand why they choose these two values instead of the other one, which is the repeated eigenvalue 1:

eigenvalue 5

$\displaystyle \left[ \begin{matrix} 1 \\ 1 \\ 0 \end{matrix} \right]$

eigenvalue 1 repeated value

$\displaystyle \left[ \begin{matrix} 0 \\ 0 \\ 1 \end{matrix} \right]$

$\displaystyle \left[ \begin{matrix} -1 \\ 1 \\ 0 \end{matrix} \right]$

not included in answer

$\displaystyle \left[ \begin{matrix} 1 \\ 1 \\ 0 \end{matrix} \right]$

P.S