Thread: counterexample, function help

Hey, I can't seem to get anywhere with this big question so if someone could work through this question with me so I understand that would be greatly appreciated.

a) If give a counterexample to

b) Prove

c) Using part b, prove that if is finite then fixes at least one element

I think for part c that if , I can then pick some and consider for each element .
But I can't get any of part a,b or c anyway.


Thanks guys for any help you can give me.

what is ?

M is the group of all rigid motions of the plane, n is dimension.

do these rigid motions have to be origin-preserving? if not, then we can let g(x) = x + a, where a is any (non-origin) point in R^n.

then g(x+y) = x + y + a, whereas g(x) + g(y) = x + y + 2a.

Originally Posted by Deveno

do these rigid motions have to be origin-preserving? if not, then we can let g(x) = x + a, where a is any (non-origin) point in R^n.

then g(x+y) = x + y + a, whereas g(x) + g(y) = x + y + 2a.

well M is the coarsest classification of orientation-preserving and orientation-reversing motion, and g(x)=x+a is a translation and thus, orientation-preserving. So you answer makes perfect sense, thanks.

Any thoughts on part b and c?

I have thought of an approach for part c, but it does not use part b.

Any help here.

Thanks

I have thought of doing it like [tex]g(\frac{1}{a}
sorry gys my computer is stuffing up and my working is wrong, any help

If G is finite then every element of G must be a rotation or a reflection. So I get the rough idea behind part c, but I can't get part b.

Any help at all?
Thanks