Having trouble converting parametric equations to skew line equations!

line 1- x=1+2r, y=1+2r, z= -3+r

line 2- x=-2, y=s, z =2+s

a.) Show that these lines are perpendicular to vector v=

[1

-2

2]

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- Oct 12th 2011, 02:03 AMjnow2vectors and points in skew lines given parametric equations
Having trouble converting parametric equations to skew line equations!

line 1- x=1+2r, y=1+2r, z= -3+r

line 2- x=-2, y=s, z =2+s

a.) Show that these lines are perpendicular to vector v=

[1

-2

2] - Oct 12th 2011, 02:39 AMPlatoRe: vectors and points in skew lines given parametric equations
- Oct 12th 2011, 03:17 AMjnow2Re: vectors and points in skew lines given parametric equations
Thankyou! but cross product for the vector of line 2 keeps equaling 4 and not 0?

- Oct 12th 2011, 03:42 AMPlatoRe: vectors and points in skew lines given parametric equations
- Oct 12th 2011, 03:42 AMHallsofIvyRe: vectors and points in skew lines given parametric equations
Cross product? You mean dot product, don't you? $\displaystyle <0, 1, 1>\cdot<1, -2, 2>= 0(1)+ 1(-2)+ 1(2)= -2+ 2= 0$

You must have dropped the "-" from -2.