Having trouble converting parametric equations to skew line equations!

line 1- x=1+2r, y=1+2r, z= -3+r

line 2- x=-2, y=s, z =2+s

a.) Show that these lines are perpendicular to vector v=

[1

-2

2]

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- October 12th 2011, 03:03 AMjnow2vectors and points in skew lines given parametric equations
Having trouble converting parametric equations to skew line equations!

line 1- x=1+2r, y=1+2r, z= -3+r

line 2- x=-2, y=s, z =2+s

a.) Show that these lines are perpendicular to vector v=

[1

-2

2] - October 12th 2011, 03:39 AMPlatoRe: vectors and points in skew lines given parametric equations
- October 12th 2011, 04:17 AMjnow2Re: vectors and points in skew lines given parametric equations
Thankyou! but cross product for the vector of line 2 keeps equaling 4 and not 0?

- October 12th 2011, 04:42 AMPlatoRe: vectors and points in skew lines given parametric equations
- October 12th 2011, 04:42 AMHallsofIvyRe: vectors and points in skew lines given parametric equations
Cross product? You mean dot product, don't you?

You must have dropped the "-" from -2.